Convert the given complex number in polar form -3 and evaluate

Asked by Abhisek | 1 year ago |  66

##### Solution :-

The complex number is -3

Let rcosθ = -3 and rsinθ = 0

$$r^2cos^2θ + r^2sin^2θ = (-3)^2$$

$$r^2(cos^2θ + sin^2θ) =9$$

$$r^2=9$$

$$r=\sqrt{9}=3$$

3cosθ = -3 and 3sinθ = 0

cosθ = -1 and sin = 0

θ = π

-3 = rcosθ + irsinθ =

3cosπ + i3sinπ

= 3(cosπ + isinπ)

Required polar form

Answered by Pragya Singh | 1 year ago

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