The complex number is -3
Let rcosθ = -3 and rsinθ = 0
Squaring and adding
\( r^2cos^2θ + r^2sin^2θ = (-3)^2\)
\( r^2(cos^2θ + sin^2θ) =9\)
\( r^2=9\)
\( r=\sqrt{9}=3\)
3cosθ = -3 and 3sinθ = 0
cosθ = -1 and sin = 0
θ = π
-3 = rcosθ + irsinθ =
3cosπ + i3sinπ
= 3(cosπ + isinπ)
Required polar form
Answered by Pragya Singh | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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