The complex number is i
Let rcosθ = 0 and rsinθ = 1
Squaring and adding
\( r^2cos^2θ + r^2sin^2θ = 0^2+1^2\)
\( r^2(cos^2θ + sin^2θ) =1\)
\( r^2=1 \)
\( r=\sqrt{1}=1\) [Conventionally, r > 0]
cosθ = 0 and sinθ = 1
\( θ =\dfrac{\pi}{2}\)
i = rcosθ + irsinθ
= \( cos\dfrac{\pi}{2}+ isin\dfrac{\pi}{2}\)
Required polar form
Answered by Pragya Singh | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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