Given quadratic equation,
x2 + 3x + 9 = 0
On comparing it with ax2 + bx + c = 0, we have
a = 1, b = 3, and c = 9
So, the discriminant of the given equation will be
D = b2 – 4ac = 32 – 4 × 1 × 9 = 9 – 36
= –27
Hence, the required solutions are:
\(\dfrac{-b\pm\sqrt{D}}{2a}\)
= \( \dfrac{-3\pm\sqrt{-27}}{2\times 1}\)
= \( \dfrac{-3\pm3\sqrt{3i}}{2}\)
Answered by Pragya Singh | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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