Quadratic equation \( \sqrt{2}x^2 + x + \sqrt{2} = 0\)
On comparing it with ax2 + bx + c = 0, we have
a = \( \sqrt{2}\), b = 1, and c = \( \sqrt{2}\)
So, the discriminant of the given equation is
D = b2 – 4ac
= \( (1)^2 – 4 × \sqrt{2} × \sqrt{2}\)
= 1 – 8 = –7
Hence, the required solutions are:
\( \dfrac{-b\pm\sqrt{D}}{2a}\)
= \( \dfrac{-1\pm\sqrt{-7}}{2\times \sqrt{2}}\)
= \( \dfrac{-1\pm\sqrt{7i}}{2 \sqrt{2}}\)
Answered by Pragya Singh | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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