Given quadratic equation,
\( x^2 + \dfrac{x}{\sqrt{2}} + 1 = 0\)
It can be rewritten as,
\( \sqrt{2}x^2 + x + \sqrt{2} = 0\)
On comparing it with ax2 + bx + c = 0, we have
a = \( \sqrt{2} \), b = 1, and c = \( \sqrt{2} \)
So, the discriminant of the given equation is
D = b2 – 4ac = (1)2 – 4 × \( \sqrt{2} \) × \( \sqrt{2} \)
= 1 – 8 = -7
Hence, the required solutions are:
\( \dfrac{-b\pm\sqrt{D}}{2a}= \dfrac{-(1)\pm\sqrt{-7}}{2\times \sqrt{2}}\)
= \( \dfrac{-1\pm\sqrt{7}i}{2\sqrt{2}}\)
Answered by Pragya Singh | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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