Given quadratic equation, \( 3x^2 – 4x + \dfrac{20}{3} = 0\)
It can be re-written as: 9x2 – 12x + 20 = 0
On comparing it with ax2 + bx + c = 0, we get
a = 9, b = –12, and c = 20
So, the discriminant of the given equation will be
D = b2 – 4ac = (–12)2 – 4 × 9 × 20
= 144 – 720 = –576
Hence, the required solutions are
\( \dfrac{-b\pm\sqrt{D}}{2a}\)
= \( \dfrac{-(12)\pm\sqrt{-576}}{2\times 9}\)
= \( \dfrac{12\pm\sqrt{576i}}{18}\)
= \( \dfrac{12\pm 24i}{18}\)
= \( \dfrac{6(2\pm 4i)}{18}\)
= \( \dfrac{2\pm 4i}{3}\)
= \( \dfrac{2}{3}\pm \dfrac{4}{3}i\)
Hence, solved
Answered by Abhisek | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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