Given quadratic equation, \( x^2 – 2x + \dfrac{3}{2} = 0\)
It can be re-written as 2x2 – 4x + 3 = 0
On comparing it with ax2 + bx + c = 0, we get
a = 2, b = –4, and c = 3
So, the discriminant of the given equation will be
D = b2 – 4ac = (–4)2 – 4 × 2 × 3
= 16 – 24 = –8
Hence, the required solutions are
\( \dfrac{-b\pm\sqrt{D}}{2a}\)
\(= \dfrac{-(-4)\pm\sqrt{8}}{2\times 2}\)
=\( \dfrac{4\pm2\sqrt{2i}}{4}\)
= \( \dfrac{2\pm\sqrt{2i}}{2}\)
= \(1\pm \dfrac{\sqrt{2}}{2}i \)
Hence, solved
Answered by Abhisek | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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