Given quadratic equation, 27x2 – 10x + 1 = 0
On comparing it with ax2 + bx + c = 0, we get
a = 27, b = –10, and c = 1
So, the discriminant of the given equation will be
D = b2 – 4ac = (–10)2 – 4 × 27 × 1 = 100 – 108 = –8
Hence, the required solutions are
\( \dfrac{-b\pm\sqrt{D}}{2a}\)
= \( \dfrac{-(-10)\pm\sqrt{-8}}{2\times 27}\)
= \( \dfrac{(10)\pm2\sqrt{2i}}{54}\)
= \( \dfrac{5\pm\sqrt{2i}}{27}\)
= \( \dfrac{5}{27}\pm \dfrac{\sqrt{2}}{27}i\)
Hence, solved
Answered by Abhisek | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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