Solve the equation 27x2 – 10x + 1 = 0

Asked by Pragya Singh | 1 year ago |  81

##### Solution :-

Given quadratic equation, 27x2 – 10x + 1 = 0

On comparing it with ax2 + bx + c = 0, we get

a = 27, b = –10, and c = 1

So, the discriminant of the given equation will be

D = b2 – 4ac = (–10)2 – 4 × 27 × 1 = 100 – 108 = –8

Hence, the required solutions are

$$\dfrac{-b\pm\sqrt{D}}{2a}$$

$$\dfrac{-(-10)\pm\sqrt{-8}}{2\times 27}$$

$$\dfrac{(10)\pm2\sqrt{2i}}{54}$$

$$\dfrac{5\pm\sqrt{2i}}{27}$$

$$\dfrac{5}{27}\pm \dfrac{\sqrt{2}}{27}i$$

Hence, solved

Answered by Abhisek | 1 year ago

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