Expression

(a + ib)(c + id)(e + if)(g + ih) = A + iB

|(a + ib)(c + id)(e + if)(g + ih) |=|A + iB|

|(a + ib) |×| (c + id) |×| (e + if) |×| (g + ih) |=|A + iB|

\( Q[|z_1z_2|=|z_1||z_2|]\)

\( \sqrt{a^2+b^2}\times \sqrt{c^2+d^2}\times \sqrt{e^2+f^2}\times\)

\( \sqrt{g^2+h^2}=\times \sqrt{A^2+B^2}\)

By squaring

\((a^2+b^2)(c^2+d^2)(e^2+f^2)\)

\((g^2+h^2)(A^2+B^2)\)

Hence, proved

Answered by Pragya Singh | 1 year agoShow that 1 + i^{10} + i^{20} + i^{30} is a real number?

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