Find the value of the trigonometric function $$tan=\dfrac{19\pi}{3}$$

Asked by Pragya Singh | 1 year ago |  70

##### Solution :-

We know that the values of tanx repeat after an interval of π or 180° .Therefore we can write,

$$tan=\dfrac{19\pi}{3}$$

$$tan6\dfrac{1}{3}\pi$$

$$tan(6\pi+\dfrac{\pi}{3})$$

$$tan\dfrac{\pi}{3}$$

$$\sqrt{3}$$

Answered by Abhisek | 1 year ago

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