Find the principal and general solutions of the question $$tanx=\sqrt{3}$$

Asked by Pragya Singh | 1 year ago |  94

##### Solution :-

Here given that,

$$tanx=\sqrt{3}$$

We know that

$$tan\dfrac{\pi}{3}=\sqrt{3}$$

and $$tan\dfrac{4\pi}{3}= tan(\pi+\dfrac{\pi}{3})$$

$$= tan\dfrac{\pi}{3}=\sqrt{3}$$

Therefore, the principal solutions are

$$x= \dfrac{\pi}{3}$$ and $$\dfrac{4\pi}{3}$$

Now, $$tanx=tan\dfrac{\pi}{3}$$

Which implies,

$$x=n\pi + \dfrac{\pi}{3},n\in Z$$

Answered by Abhisek | 1 year ago

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