Find $$\lim\limits_{x \to 5}f(x)$$ where $$f(x)=|x|-5$$

Asked by Abhisek | 1 year ago |  64

Solution :-

The given function is $$f(x) =|x|-5$$

$$\lim\limits_{x \to 5^-}f(x)= \lim\limits_{x \to 5^-}(|x|-5)$$

$$\lim\limits_{x \to 5}(x-5)$$

= 5-5 = 0

$$\lim\limits_{x \to 5^+}f(x)= \lim\limits_{x \to 5^+}(|x|-5)$$

$$\lim\limits_{x \to 5}(x-5)$$

= 5-5=0

$$\lim\limits_{x \to 5^-}f(x)= \lim\limits_{x \to 5^+}f(x)=0$$

Hence, $$\lim\limits_{x \to 5}f(x)=0$$

Answered by Pragya Singh | 1 year ago

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