Let f(x) = x2-2 Accordingly,
\( f'(10)=\lim\limits_{h \to 0}\dfrac{f(10+h)-f(10)}{h}\)
\(\lim\limits_{h \to 0}\dfrac{[(10+h)^2]-(10^2-2)}{h}\)
\( \lim\limits_{h \to 0}\dfrac{10^2+2.10h+h^2-2-10^2+2}{h}\)
\( \lim\limits_{h \to 0}\dfrac{20h+h^2}{h}\)
\( \lim\limits_{h \to 0}(20+h)=20+0=10\)
Answered by Abhisek | 1 year ago