Find the derivative of f(x) = \( \dfrac{2}{x+1}-\dfrac{x^2}{3x-1}\)

Asked by Abhisek | 1 year ago |  57

1 Answer

Solution :-

\( f'(x)= \dfrac{d}{dx}(\dfrac{2}{x+1})-\dfrac{d}{dx} (\dfrac{x^2}{3x-1})\)

By quotient rule,

\(- \dfrac{2}{(x+1)^2}-[\dfrac{6x^2-2x-3x^2}{(3x-1)^2}]\)

\( - \dfrac{2}{(x+1)^2}-\dfrac{x(3x-2)}{(3x-1)^2}\)

Answered by Pragya Singh | 1 year ago

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