Find the derivative of the functions: 5sec x + 4cos x

Asked by Abhisek | 1 year ago |  56

##### Solution :-

$$f'(x)=\lim\limits_{h \to 0}\dfrac{f(x+h)-f(x)}{h}$$

$$f(x)= 5 sec x + 4 cos x$$

$$f(x)= \dfrac{d}{dx}(5secx+4cosx)$$

By further calculation, we get

$$5\dfrac{d}{dx}(secx)+4\dfrac{d}{dx}(cosx)$$

$$5 \;secx\; tanx + 4 \times (-sinx)$$

$$5 \;secx \;tanx - 4 sinx$$

Answered by Pragya Singh | 1 year ago

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