Find the derivative of the functions: cosec x

Asked by Abhisek | 1 year ago |  50

1 Answer

Solution :-

\( f'(x)=\lim\limits_{h \to 0}\dfrac{f(x+h)-f(x)}{h} \)

\( \lim\limits_{h \to 0} \dfrac{1}{h}[cosec(x+h)-cosecx]\)

\( \lim\limits_{h \to 0} \dfrac{1}{h}[\dfrac{1}{sin(x+h)}-\dfrac{1}{sinx}]\)

\( \lim\limits_{h \to 0} \dfrac{1}{h}[\dfrac{sinx-sin(x+h)}{sinxsin(x+h)}]\)

\(- \dfrac{1}{sinx}\times 1\times \dfrac{cos(\dfrac{2x+0}{2})}{sin(x+0)}\)

\(- \dfrac{1}{sinx}\times \dfrac{cosx}{sinx}\)

= -cosecxcotx 

Answered by Pragya Singh | 1 year ago

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