Let f(x) = x + a. Accordingly, f(x + h) = x + h + a By first principle,

\( f'(x)=\lim\limits_{h \to 0}\dfrac{f(x+h)-f(x)}{h}
\)

\(\lim\limits_{h \to 0}\dfrac{x+h+a-x-a}{h}
\)

\(\lim\limits_{h \to 0}(\dfrac{h}{h})\)

\( \lim\limits_{h \to 0}(1)
\)

= 1

Answered by Abhisek | 2 years ago