Let f '(x) = (ax +b)(cx + d)2 By Leibnitz product rule,
\( f(x)=(ax+b)\dfrac{d}{dx}(cx+d)^2\dfrac{d}{dx}(ax+b)\)
\( f(x)=(ax+b)\dfrac{d}{dx}(c^2x^2
+2cdx^2)\)
\( +(cx+d)^2\dfrac{d}{dx}(ax+b)\)
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=(ax+b)(2c2x +2cd)+(cx +d)2a
=2c(ax +b)(cx + d)+ a(cx + d)2
Answered by Abhisek | 1 year ago