Find the derivative of the following functions (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

$$\dfrac{x^2cos(\dfrac{\pi}{4})}{sinx}$$

Asked by Abhisek | 1 year ago |  115

Solution :-

Let f(x)=​​​ ​​​​$$\dfrac{x^2cos(\dfrac{\pi}{4})}{sinx}$$

By quotient rule,

$$cos(\dfrac{\pi}{4})[\dfrac{sinx(2x)-x^2(cosx)}{sin^2x}]$$

$$\dfrac{ xcos\dfrac{\pi}{4}[2sinx-xcosx]}{sin^2x}$$

Answered by Pragya Singh | 1 year ago

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