Value of k, for which $$A=\bigl[\begin{smallmatrix} k&8 \\ 4&2k \end{smallmatrix} \bigr]$$ is a singular matrix is:

(a) 4

(b) -4

(c) ±4

(d) 0

Asked by Abhisek | 1 year ago |  66

##### Solution :-

Explanation:-

As A is singular matrix

$$|A|=0$$

$$2k^2−32=0 =k=±4$$

Answered by Pragya Singh | 1 year ago

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