Given that the farmer covers the entire boundary of the square field in 40 seconds, the total distance travelled by the farmer in 40 seconds is \( 4\times(10) = 40\, meters\)

Therefore, the average distance covered by the farmer in one second is: \( \frac{40\,m}{1\,m}=1\,m\)

Two minutes and 20 seconds can be written as 140 seconds. The total distance travelled by the farmer in this timeframe is: \( 1\,m\,\times\,140=140\,m\)

Since the farmer is moving along the boundary of the square field, the total number of laps completed by the farmer will be:\( \frac{140}{40}=3.5\,laps\)

Now, the total displacement of the farmer depends on the initial position. If the initial position of the farmer is at one corner of the field, the terminal position would be at the opposite corner (since the field is square).

In this case, the total displacement of the farmer will be equal to the length of the diagonal line across the opposite corners of the square.

Applying the Pythagoras theorem, the length of the diagonal can be obtained as follows:\(\sqrt{10+10^2}=\sqrt{200}=14.14\,m\)

This is the maximum possible displacement of the farmer.

If the initial position of the farmer is at the mid-point between two adjacent corners of the square, the net displacement of the farmer would be equal to the side of the square, which is 10 m. This is the minimum displacement.

If the farmer starts at a random point around the perimeter of the square, his net displacement after travelling 140 m will lie between 10 m and 14.14 m.

Answered by Shivani Kumari | 1 year ago**A bus starting from rest moves with a uniform acceleration of 0.1 m s ^{-2} for 2 minutes. Find**

**(a)** the speed acquired,

**(b) **the distance traveled.

What is the quantity which is measured by the area occupied below the velocity-time graph?

**A bus starting from rest moves with a uniform acceleration of 0.1 m s ^{-2} for 2 minutes. Find**

**(a)** the speed acquired,

**(b)** the distance travelled.

What can you say about the motion of an object if its speed-time graph is a straight line parallel to the time axis?

What can you say about the motion of an object whose distance-time graph is a straight line parallel to the time axis?