\(\frac{x}{3} + 1 = \frac{7}{15}\)
Transposing 1 to R.H.S, we obtain
\(\frac{x}{3} = \frac{7}{15} - 1\)
\(\frac{x}{3} = \frac{7-15}{15} \)
\(\frac{x}{3} = -\frac{8}{15} \)
Multiplying both sides by 3, we obtain
\(\frac{x}{3} \times 3 = -\frac{8}{15} \times 3\)
x = \(-\frac{8}{15}\)
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