Let the breadth be x m. The length will be (2x + 2) m.
Perimeter of swimming pool = 2(l + b) = 154 m
2(2x + 2 + x) = 154
2(3x + 2) = 154
Dividing both sides by 2, we obtain
\(\frac{2(3x + 2)}{2} = \frac{154}{2}\)
3x + 2 = 77
On transposing 2 to R.H.S, we obtain
3x = 77 - 2
3x = 75
On dividing both sides by 3, we obtain
\(\frac{3x}{3} = \frac{75}{3}\)
x = 25
2x + 2 = 25 + 2 = 52
Hence, the breadth and length of the pool are 25 m and 52 m respectively.
Answered by Sakshi | 1 year agoSolve the inequations and graph their solutions on a number line – 1 < (\( \dfrac{x}{2}\)) + 1 ≤ 3, x ε l
Solve the inequations and graph their solutions on a number line – 4 ≤ 4x < 14, x ε N
Solve (\( \dfrac{x}{3}\)) + (\( \dfrac{1}{4}\)) < (\( \dfrac{x}{6}\)) + (\( \dfrac{1}{2}\)), x ε W. Also represent its solution on the number line.
If the replacement set is {-3, -2, -1, 0, 1, 2, 3}, solve the inequation \(\dfrac {(3x – 1) }{2} < 2\). Represent its solution on the number line.
Solve the inequations (\( \dfrac{3}{2}\)) – (\( \dfrac{x}{2}\)) > – 1, x ε N