Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?

Asked by Aaryan | 1 year ago |  134

##### Solution :-

Let the common ratio between these numbers be x. Therefore, the numbers will be 5xand 3xrespectively.

Difference between these numbers = 18

5x - 3x= 18

2x= 18

Dividing both sides by 2,

$$\frac{2x}{2} = \frac{18}{2}$$

x = 9

First number = 5x= 5 × 9 = 45

Second number = 3x= 3 × 9 = 27

Answered by Sakshi | 1 year ago

### Related Questions

#### Solve the inequations and graph their solutions on a number line  – 1 < (x / 2) + 1 ≤ 3, x ε l

Solve the inequations and graph their solutions on a number line  – 1 < ($$\dfrac{x}{2}$$) + 1 ≤ 3, x ε l

#### Solve the inequations and graph their solutions on a number line – 4 ≤ 4x < 14, x ε N

Solve the inequations and graph their solutions on a number line – 4 ≤ 4x < 14, x ε N

#### Solve (x / 3) + (1 / 4) < (x / 6) + (1 / 2), x ε W. Also represent its solution on the number line.

Solve ($$\dfrac{x}{3}$$) + ($$\dfrac{1}{4}$$) < ($$\dfrac{x}{6}$$) + ($$\dfrac{1}{2}$$), x ε W. Also represent its solution on the number line.

If the replacement set is {-3, -2, -1, 0, 1, 2, 3}, solve the inequation $$\dfrac {(3x – 1) }{2} < 2$$. Represent its solution on the number line.
Solve the inequations ($$\dfrac{3}{2}$$) – ($$\dfrac{x}{2}$$) > – 1, x ε N