Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.

Asked by Aaryan | 1 year ago |  205

##### Solution :-

Let three consecutiveintegers be x, x + 1, x+ 2. According to the question,

2x + 3(x+ 1) + 4(x+ 2) = 74

2x+ 3x + 3 + 4x + 8 = 74

9x+ 11 = 74

On transposing 11 to R.H.S, we obtain

9x= 74 - 11

9x= 63

On dividing both sides by 9, we obtain

$$\frac{9x}{9} = \frac{63}{9}$$

x= 7

x+ 1 = 7 + 1 = 8

x+ 2 = 7 + 2 = 9

Hence, the numbers are 7, 8, and 9.

Answered by Sakshi | 1 year ago

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