Let Shobo's age be x years. Therefore, his mother's age will be 6x years.
According to the given question,
After 5 year, shobo's age = \( \frac{shobo's\, mother's\,present\,age}{3}\)
x + 5 = \(\frac{6x}{3}\)
x + 5 = 2x
Transposing x to R.H.S, we obtain
5 = 2x - x
5 = x
6x = 6 × 5 = 30
Therefore, the present ages of Shobo and Shobo's mother will be 5 years and 30 years respectively.
Answered by Aaryan | 1 year agoSolve the inequations and graph their solutions on a number line – 1 < (\( \dfrac{x}{2}\)) + 1 ≤ 3, x ε l
Solve the inequations and graph their solutions on a number line – 4 ≤ 4x < 14, x ε N
Solve (\( \dfrac{x}{3}\)) + (\( \dfrac{1}{4}\)) < (\( \dfrac{x}{6}\)) + (\( \dfrac{1}{2}\)), x ε W. Also represent its solution on the number line.
If the replacement set is {-3, -2, -1, 0, 1, 2, 3}, solve the inequation \(\dfrac {(3x – 1) }{2} < 2\). Represent its solution on the number line.
Solve the inequations (\( \dfrac{3}{2}\)) – (\( \dfrac{x}{2}\)) > – 1, x ε N