(i) x + 100° = 180° (Adjacent angles are supplementary)
x = 80°
z = x = 80º(Opposite angles are equal)
y = 100° (Opposite angles are equal)
(ii) 50° + y = 180° (Adjacent angles are supplementary)
y = 130°
x = y = 130° (Opposite angles are equal)
z = x = 130º (Corresponding angles)
(iii) x = 90° (Vertically opposite angles)
x + y + 30° = 180° (Angle sum property of triangles)
120° + y = 180°
y = 60°
z = y = 60° (Alternate interior angles)
(iv) z = 80° (Corresponding angles)
y = 80° (Opposite angles are equal)
x+ y = 180° (Adjacent angles are supplementary)
x = 180° - 80° = 100°
(v) y = 112° (Opposite angles are equal)
x+ y + 40° = 180° (Angle sum property of triangles)
x + 112° + 40° = 180°
x + 152° = 180°
x = 28°
z = x = 28° (Alternate interior angles)
Answered by Sakshi | 1 year agoIn the given figure, PQRS is a kite. Find the values of x and y.
In the given isosceles trapezium ABCD, ∠C = 102°. Find all the remaining angles of the trapezium.
In the given figure, ABCD is a rhombus and ∠ABD = 50°. Find :
(i) ∠CAB
(ii) ∠BCD
(iii) ∠ADC
In the given figure, ABCD is a rectangle and diagonals intersect at O. If ∠AOB = 118°, find
(i) ∠ABO
(ii) ∠ADO
(iii) ∠OCB
In the given figure, ABCD is a rectangle. If ∠CEB : ∠ECB = 3 : 2 find
(i) ∠CEB,
(ii) ∠DCF