Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2. Let ∠A = 3x and ∠B = 2x
We know that the sum of the measures of adjacent angles is 180 º for a parallelogram.
∠A + ∠B = 180º
3x + 2x = 180º
5x = 180º
x = \(\frac{180^\circ}{5} = 36^\circ\)
∠A = ∠C = 3x = 108º (Opposite angles)
∠B = ∠D = 2x = 72º (Opposite angles)
Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º
Answered by Sakshi | 1 year agoIn the given figure, PQRS is a kite. Find the values of x and y.
In the given isosceles trapezium ABCD, ∠C = 102°. Find all the remaining angles of the trapezium.
In the given figure, ABCD is a rhombus and ∠ABD = 50°. Find :
(i) ∠CAB
(ii) ∠BCD
(iii) ∠ADC
In the given figure, ABCD is a rectangle and diagonals intersect at O. If ∠AOB = 118°, find
(i) ∠ABO
(ii) ∠ADO
(iii) ∠OCB
In the given figure, ABCD is a rectangle. If ∠CEB : ∠ECB = 3 : 2 find
(i) ∠CEB,
(ii) ∠DCF