Diameter of circular pond (d) = 17.5 m

Radius (r) =\( \dfrac{1725}{2}\) = 8.75 m

Width of path = 2m

Radius of outer cirlce (R) = 8.75 + 2 = 10.75 m

Area of path = (R^{2} – r^{2})π

= [(10.75)^{2} – (8.75)^{2}](3.14)

= 3.14(10.75 + 8.75) (10.75 – 8.75)

= 3.14 x 19.5 x 2 = 122.46 m^{2}

Cost of 1 m^{2} for constructing the path ₹25 m^{2}

Total cost = ₹ 122.46 x 25 = ₹3061.50

Answered by Aaryan | 9 months agoProve that the area of a circular path of uniform width hsurrounding a circular region of radius r is πh(2r + h).

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