Diameter of circular pond (d) = 17.5 m
Radius (r) =\( \dfrac{1725}{2}\) = 8.75 m
Width of path = 2m
Radius of outer cirlce (R) = 8.75 + 2 = 10.75 m
Area of path = (R2 – r2)π
= [(10.75)2 – (8.75)2](3.14)
= 3.14(10.75 + 8.75) (10.75 – 8.75)
= 3.14 x 19.5 x 2 = 122.46 m2
Cost of 1 m2 for constructing the path ₹25 m2
Total cost = ₹ 122.46 x 25 = ₹3061.50
Answered by Aaryan | 9 months agoProve that the area of a circular path of uniform width hsurrounding a circular region of radius r is πh(2r + h).
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