Width of the road = 7 m

Circumference of the park = 352 m

Let r be the radius, then 2πr = 352

Circumference of circular park = 352 m

= 2πr=352 where r is the radius of the park

=2×\( \dfrac{22}{7}\)×r=352

= r=56 m

Now, outer radius =56 m+7 m=63 m

Area of the road =π×63^{2}−π×56^{2}

=π(632−56^{2})

=\( \dfrac{22}{7}\)×(63+56)×(63−56)

=227×119×7=2618 m^{2}

Prove that the area of a circular path of uniform width hsurrounding a circular region of radius r is πh(2r + h).

The outer circumference of a circular race-track is 528 m. The track is everywhere 14 m wide. Calculate the cost of levelling the track at the rate of 50 paise per square metre

A circular pond is of diameter 17.5 m. It is surrounded by a 2 m wide path. Find the cost of constructing the path at the rate of ₹25 per square metre (Use π = 3.14)

A path of width 3.5 m runs around a semicircular grassy plot whose perimeter is 72 m. Find the area of the path.

Find the area enclosed between two concentric circles of radii 3.5 cm and 7 cm. A third concentric circle is drawn outside the 7 cm circle, such that the area enclosed between it and the 7 cm circle is same as that between the two inner circles. Find the radius of the third circle correct to one decimal place.