1 Answer
Solution :-
Width of the road = 7 m
Circumference of the park = 352 m
Let r be the radius, then 2πr = 352
Circumference of circular park = 352 m
= 2πr=352 where r is the radius of the park
=2×\( \dfrac{22}{7}\)×r=352
= r=56 m
Now, outer radius =56 m+7 m=63 m
Area of the road =π×632−π×562
=π(632−562)
=\( \dfrac{22}{7}\)×(63+56)×(63−56)
=227×119×7=2618 m2
Answered by Sakshi | 9 months agoRelated Questions
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