Evaluate the \( 2sin 3x = \sqrt{3}\)

Asked by Aaryan | 9 months ago |  126

1 Answer

Solution :-

Given,

2 sin 3x =\( \sqrt{3}\)

sin 3x = \( \dfrac{ \sqrt{3}}{2}\)

sin 3x = sin 60°

3x = 60°

x = 20°

Answered by Sakshi | 9 months ago

Related Questions

Evalute the following:

(i) \( \dfrac{sin 20°}{ cos 70°}\)

(ii) \(\dfrac{ cos 19°}{ sin 71°}\)

(iii) \( \dfrac{sin 21°}{ cos 69°}\)

(iv) \( \dfrac{tan 10°}{ cot 80°}\)

(v) \( \dfrac{sec 11°}{ cosec 79°}\)

Class 10 Maths Introduction to Trigonometry View Answer