Given tan-1(tan 4)
As tan-1(tan x) = x if x ϵ [\( \dfrac{-\pi}{2},\dfrac{\pi}{2}\)]
But here x = 4 which does not belongs to above range
We also have tan (π – θ) = –tan (θ)
Therefore tan (θ – π) = tan (θ)
Tan (4 – π) = tan (4)
Now 4 – π is in the given range
Hence tan–1 (tan 2) = 4 – π
Answered by Aaryan | 1 year agoEvaluate \( Cosec (cos^{-1} \dfrac{8}{17})\)
Evaluate \( tan^{-1}(tan \dfrac{9\pi}{4})\)