Given ai j = 2i – j
Let A = [ai j]2×3
So, the elements in a 2 × 3 matrix are
a11, a12, a13, a21, a22, a23
a11 = 2 × 1 – 1 = 2 – 1 = 1
a12 = 2 × 1 – 2 = 2 – 2 = 0
a13 = 2 × 1 – 3 = 2 – 3 = – 1
a21 = 2 × 2 – 1 = 4 – 1 = 3
a22 = 2 × 2 – 2 = 4 – 2 = 2
a23 = 2 × 2 – 3 = 4 – 3 = 1
Substituting these values in matrix A we get,
Construct a 4 × 3 matrix A = [ai j] whose elements ai j are given by ai j = i
Construct a 4 × 3 matrix A = [ai j] whose elements ai j are given by \( a_{i j} = \dfrac{(i – j)}{(i + j)}\)