Given ai j = 2i
Let A = [ai j]2×3
So, the elements in a 3×4 matrix are
a11, a12, a13, a14, a21, a22, a23, a24, a31, a32, a33, a34
a11 = 2×1 = 2
a12 = 2×1 = 2
a13 = 2×1 = 2
a14 = 2×1 = 2
a21 = 2×2 = 4
a22 = 2×2 = 4
a23 = 2×2 = 4
a24 = 2×2 = 4
a31 = 2×3 = 6
a32 = 2×3 = 6
a33 = 2×3 = 6
a34 = 2×3 = 6
Substituting these values in matrix A we get,
Construct a 4 × 3 matrix A = [ai j] whose elements ai j are given by ai j = i
Construct a 4 × 3 matrix A = [ai j] whose elements ai j are given by \( a_{i j} = \dfrac{(i – j)}{(i + j)}\)