(i) A ⊂ B
To show that the following four statements are equivalent, we need to prove (i)=(ii), (ii)=(iii), (iii)=(iv), (iv)=(v)
Firstly let us prove (i)=(ii)
We know, A–B = {x ∈ A: x ∉ B} as A ⊂ B,
So, Each element of A is an element of B,
∴ A–B = ϕ
Hence, (i)=(ii)
(ii) A – B = ϕ
We need to show that (ii)=(iii)
By assuming A–B = ϕ
To show: A∪B = B
∴ Every element of A is an element of B
So, A ⊂ B and so A∪B = B
Hence, (ii)=(iii)
(iii) A ∪ B = B
We need to show that (iii)=(iv)
By assuming A ∪ B = B
To show: A ∩ B = A.
∴ A⊂ B and so A ∩ B = A
Hence, (iii)=(iv)
(iv) A ∩ B = A
Finally, now we need to show (iv)=(i)
By assuming A ∩ B = A
To show: A ⊂ B
Since, A ∩ B = A, so A⊂B
Hence, (iv)=(i)
Answered by Sakshi | 1 year agoFind the symmetric difference A Δ B, when A = {1, 2, 3} and B = {3, 4, 5}.