By the definition of equality of ordered pairs,
Let us solve for a and b
\( \dfrac{a}{3}\) + 1 = \( \dfrac{5}{3}\) and \( b- \dfrac{2}{3}\) = \( \dfrac{1}{3}\)
\( \dfrac{a}{3}= \dfrac{5}{3}-1\) and \( b= \dfrac{1}{3}+ \dfrac{2}{3}\)
\(\dfrac{ a}{3} = \dfrac{(5-3)}{3}\) and \( b = \dfrac{(1+2)}{3}\)
a =\(\dfrac{ 2(3)}{3}\) and b = 1
a = 2 and b = 1
Values of a and b are, a = 2 and b = 1
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