If $$(\dfrac{a}{3} + 1, b – \dfrac{2}{3}) = (\dfrac{5}{3}, \dfrac{1}{3})$$, find the values of a and b.

Asked by Sakshi | 1 year ago |  83

##### Solution :-

By the definition of equality of ordered pairs,

Let us solve for a and b

$$\dfrac{a}{3}$$ + 1 = $$\dfrac{5}{3}$$ and $$b- \dfrac{2}{3}$$ = $$\dfrac{1}{3}$$

$$\dfrac{a}{3}= \dfrac{5}{3}-1$$ and $$b= \dfrac{1}{3}+ \dfrac{2}{3}$$

$$\dfrac{ a}{3} = \dfrac{(5-3)}{3}$$ and $$b = \dfrac{(1+2)}{3}$$

a =$$\dfrac{ 2(3)}{3}$$ and b = 1

a = 2 and b = 1

Values of a and b are, a = 2 and b = 1

Answered by Sakshi | 1 year ago

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