Given,
R is a relation from {11, 12, 13} to (8, 10, 12} defined by y = x – 3
Here,
x = {11, 12, 13} and y = (8, 10, 12}
y = x – 3
When, x = 11, y = 11 – 3 = 8 ∈ (8, 10, 12}
When, x = 12, y = 12 – 3 = 9 ∉ (8, 10, 12}
When, x = 13, y = 13 – 3 = 10 ∈ (8, 10, 12}
∴ R = {(11, 8), (13, 10)}
R‑1 = {(8, 11), (10, 13)}
Answered by Sakshi | 1 year agoLet R = {(a, b) : a, b, ϵ N and a < b}.Show that R is a binary relation on N, which is neither reflexive nor symmetric. Show that R is transitive.
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(i) Write R in roster form.
(ii) Find: dom (R) and range (R)
(iii) Write R–1 in roster form
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(i) Write R in roster form.
(ii) Find dom (R) and range (R).
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