We know that
8! = 8 × 7 × 6!
7! = 7 × 6!
So by using these values,
\( \dfrac{ x}{6!}+\dfrac{ x}{7!} =\dfrac{ x}{8!}\)
\(\dfrac{ (1 + 7)}{(7×6!) }= \dfrac{x}{8!}\)
\(\dfrac{ 8}{7! }= \dfrac{x}{(8×7!)}\)
x = \(\dfrac{ (8 × 8 × 7!)}{7!}\)
= 8 × 8
= 64
The value of x is 64.
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