We know that, each AP consists of a unique first term and a common difference.
So, number of ways to select the first term of a given set is 3C1 = 3
And, number of ways to select a common difference of given set is 5C1 = 5
Hence, total number of AP’s possible are 3C1 × 5C1 = 3 × 5 = 15
Answered by Sakshi | 1 year agoHow many words each of 3 vowels and 2 consonants can be formed from the letters of the word INVOLUTE?
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