How many three-digit numbers are there?

Asked by Aaryan | 1 year ago |  32

##### Solution :-

Let us assume we have three boxes.

The first box can be filled with any one of the nine digits (zero not allowed at first position)

So, possibilities are 9C1

The second box can be filled with any one of the ten digits

So the available possibilities are 10C1

Third box can be filled with any one of the ten digits

So the available possibilities are 10C1

Hence, the total number of possible outcomes are 9C1 × 10C1 × 10C1 = 9 × 10 × 10 = 900.

Answered by Sakshi | 1 year ago

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