Let us assume there are six seats.
In the first seat, any one of six members can be seated, so the total number of possibilities is 6C1
In the second seat, any one of five members can be seated, so the total number of possibilities is 5C1 ways.
In the third seat, any one of four members can be seated, so the total number of possibilities is 4C1 ways.
In the fourth seat, any one of three members can be seated, so the total number of possibilities is 3C1 ways.
In the fifth seat, any one of two members can be seated, so the total number of possibilities is 2C1 ways.
In the sixth seat, only one remaining person can be seated, so the total number of possibilities is 1C1 ways.
Hence, the total number of possible outcomes = 6C1 × 5C1 × 4C1 × 3C1 × 2C1 × 1C1 = 6 × 5 × 4 × 3 × 2 × 1 = 720.
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