Number of arrangements of ‘n’ things taken all at a time = P (n, n)
The total number of ways in which five children can stand in a queue = the number of arrangements of 5 things taken all at a time = P (5, 5)
So,
P (5, 5) = \( \dfrac{5!}{(5 – 5)!}\)
= 5! [Since, 0! = 1]
= 5 × 4 × 3 × 2 × 1
= 120
Hence, Number of ways in which five children can stand in a queue are 120.
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