Given:
The word ‘ALGEBRA’
There are 4 consonants in the word ‘ALGEBRA’
The number of ways to arrange these consonants is 4P4 = 4!
There are 3 vowels in the word ‘ALGEBRA’ of which, 2 are A’s
So vowels can be arranged in = \( \dfrac{3! }{ 2!}\) Ways
Hence, the required number of arrangements = 4! × (\( \dfrac{3! }{ 2!}\))
= 4×3×2×1×3 = 72
Answered by Sakshi | 1 year agoHow many words each of 3 vowels and 2 consonants can be formed from the letters of the word INVOLUTE?
Find the number of permutations of n distinct things taken r together, in which 3 particular things must occur together.
How many words, with or without meaning can be formed from the letters of the word ‘MONDAY’, assuming that no letter is repeated, if
(i) 4 letters are used at a time
(ii) all letters are used at a time
(iii) all letters are used but first letter is a vowel ?
There are 10 persons named P1, P2, P3 …, P10. Out of 10 persons, 5 persons are to be arranged in a line such that is each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.
How many different words, each containing 2 vowels and 3 consonants can be formed with 5 vowels and 17 consonants?