Given:
The digits 1, 3, 3, 0
Total number of digits = 4
Digits of the same type = 2
Total number of 4 digit numbers = \( \dfrac{4! }{ 2!}\)
Where, zero cannot be the first digit of the four digit numbers.
So, Total number of 3 digit numbers = \( \dfrac{3! }{ 2!}\)
Total number of Numbers = \( \dfrac{4! }{ 2!} – \dfrac{3! }{ 2!}\)
= [4×3] – [3]
= 12 – 3
= 9
Hence, total number of four digit can be formed is 9.
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