Given:

The word ‘SERIES’

There are 6 letters in the word ‘SERIES’ out of which 2 are S’s, 2 are E’s and the rest all are distinct.

Now, Let us fix 5 letters at the extreme left and also at the right end. So we are left with 4 letters of which 2 are E’s.

These 4 letters can be arranged in = \(\dfrac{ 4! }{ 2!}\) Ways.

Required number of arrangements is = \( \dfrac{ 4! }{ 2!}\)

= 4 × 3

= 12

Hence, a total number of arrangements of the letters of the word ‘SERIES’ in such a way that the first and last position is always occupied by the letter S is 12.

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