How many different boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls?

Asked by Aaryan | 2 years ago |  65

#### 1 Answer

##### Solution :-

Given:

Total boys are = 25

Total girls are = 10

Boat party of 8 to be made from 25 boys and 10 girls, by selecting 5 boys and 3 girls.

So,

By using the formula,

nCr = $$\dfrac{ n!}{r!(n – r)!}$$

25C5 × 10C3 = $$\dfrac{ 25!}{5!(25 – 5)!} × \dfrac{10!}{3!(10-3)!}$$

= 5×2×23×11×21 × 5×3×8

= 53130 × 120

= 6375600

The total number of different boat parties is 6375600 ways.

Answered by Sakshi | 2 years ago

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