**(i)** (5, 2, 3)

In this case, since x, y and z all three are positive then octant will be XOYZ

**(ii)** (-5, 4, 3)

In this case, since x is negative and y and z are positive then the octant will be X′OYZ

**(iii)** (4, -3, 5)

In this case, since y is negative and x and z are positive then the octant will be XOY′Z

**(iv)** (7, 4, -3)

In this case, since z is negative and x and y are positive then the octant will be XOYZ′

**(v)** (-5, -4, 7)

In this case, since x and y are negative and z is positive then the octant will be X′OY′Z

**(vi)** (-5, -3, -2)

In this case, since x, y and z all three are negative then octant will be X′OY′Z′

**(vii)** (2, -5, -7)

In this case, since z and y are negative and x is positive then the octant will be XOY′Z′

**(viii)** (-7, 2, -5)

In this case, since x and z are negative and x is positive then the octant will be X′OYZ′

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