(i) (5, 2, 3)
In this case, since x, y and z all three are positive then octant will be XOYZ
(ii) (-5, 4, 3)
In this case, since x is negative and y and z are positive then the octant will be X′OYZ
(iii) (4, -3, 5)
In this case, since y is negative and x and z are positive then the octant will be XOY′Z
(iv) (7, 4, -3)
In this case, since z is negative and x and y are positive then the octant will be XOYZ′
(v) (-5, -4, 7)
In this case, since x and y are negative and z is positive then the octant will be X′OY′Z
(vi) (-5, -3, -2)
In this case, since x, y and z all three are negative then octant will be X′OY′Z′
(vii) (2, -5, -7)
In this case, since z and y are negative and x is positive then the octant will be XOY′Z′
(viii) (-7, 2, -5)
In this case, since x and z are negative and x is positive then the octant will be X′OYZ′
Answered by Aaryan | 1 year agoA(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle ∠BAC meets BC.
The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C.
If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divided AB.
Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane x + y + z = 5.
Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane.