Given:

Total number of players = 16

Number of players to be selected = 11

So, the combination is ^{16}C_{11}

By using the formula,

^{n}C_{r} =\( \dfrac{ n!}{r!(n – r)!}\)

^{16}C_{11} = \( \dfrac{16! }{ 11! (16 – 11)!}\)

= 4×7×13×12

= 4368

**(i) **Include 2 particular players?

It is told that two players are always included.

Now, we have to select 9 players out of the remaining 14 players as 2 players are already selected.

Number of ways = ^{14}C_{9}

^{14}C_{9} =\(\dfrac{ 14! }{ 9! (14 – 9)!}\)

= 7×13×11×2

= 2002

**(ii)** Exclude 2 particular players?

It is told that two players are always excluded.

Now, we have to select 11 players out of the remaining 14 players as 2 players are already removed.

Number of ways = ^{14}C_{9}

^{14}C_{11} = \(\dfrac{ 14! }{ 11! (14 – 11)!}\)

= 14×13×2

= 364

The required no. of ways are 4368, 2002, 364.

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