1 Answer
Solution :-
Given that we need to find the no. of ways of obtaining a product by multiplying two or more from the numbers 3, 5, 7, 11.
Number of ways = (no. of ways of multiplying two numbers) + (no. of ways of multiplying three numbers) + (no. of multiplying four numbers)
= 4C2 + 4C3 + 4C4
By using the formula,
nCr =\( \dfrac{ n!}{r!(n – r)!}\)
= \( \dfrac{12}{2}\) + 4 + 1
= 6 + 4 + 1
= 11
The total number of ways of product is 11 ways.
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