From 4 officers and 8 jawans in how many ways can 6 be chosen

(i) to include exactly one officer

(ii) to include at least one officer?

Asked by Aaryan | 1 year ago |  33

1 Answer

Solution :-

Given:

Total number of officers = 4

Total number of jawans = 8

Total number of selection to be made is 6

(i) to include exactly one officer

Number of ways = (no. of ways of choosing 1 officer from 4 officers) × (no. of ways of choosing 5 jawans from 8 jawans)

= (4C1) × (8C5)

By using the formula,

nCr = \( \dfrac{ n!}{r!(n – r)!}\)

RD Sharma Solutions for Class 11 Maths Chapter 17 – Combinations image - 7

(ii) to include at least one officer?

Number of ways = (total no. of ways of choosing 6 persons from all 12 persons) – (no. of ways of choosing 6 persons without any officer)

12C6 – 8C6

By using the formula,

nCr = \( \dfrac{ n!}{r!(n – r)!}\)

RD Sharma Solutions for Class 11 Maths Chapter 17 – Combinations image - 8

= (11×2×3×2×7) – (4×7)

= 924 – 28

= 896 ways

The required no. of ways are 224 and 896.

Answered by Sakshi | 1 year ago

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